Another 4C opening... Calculation help needed
#1
Posted 2008-February-21, 03:56
4♣ pass ??
♠xx
♥KQJx
♦AKxx
♣Axx
4♣ shows ♣HHxxxxxx and nothing outside.
♠AK and ♥A are missing.
Let's say, it is good to raise 4♣ to 5♣ whenever opener has some of distributions:
0238
0328
1138
1318
1248
2038
3028.
(cannot have 4M)
Watching 2♠4♥4♦ what is the chance 5♣ will make (supposing partner has the ♣K)?
#3
Posted 2008-February-21, 04:34
Edit: this means bidding game is about a 61% proposition
This post has been edited by cardsharp: 2008-February-21, 05:00
#4
Posted 2008-February-21, 04:36
it is close, you have 3 1/2 tricks for
partner.
Most likely I bid 5C.
With kind regards
Marlowe
Uwe Gebhardt (P_Marlowe)
#5
Posted 2008-February-21, 04:43
4m is a very effective preempt. I think you are wasting chances to use it by insisting a 4m opening follow your 'HHxxxxxx and nothing outside' rule.
#6
Posted 2008-February-21, 04:58
655321, on Feb 21 2008, 11:43 AM, said:
"Nothing outside" in terms of A, K or QQ - to be sure the risk of losing 3NT is minimal.
#7
Posted 2008-February-21, 05:04
cardsharp, on Feb 21 2008, 11:34 AM, said:
What constraints you used?
Can you repeat, please, a simulation with these:
- fix: ♣KQJxxxxx;
- fix: 6-8 HCP (no big values outside, max Q or JJ);
- fix: no 4M, no 4♦.
TY.
P.S. What program do you use for these simulations?
#8
Posted 2008-February-21, 05:25
cardsharp, on Feb 21 2008, 11:34 AM, said:
Edit: this means bidding game is about a 61% proposition
Amazing. The a priori probability of having 2+ spades and 1+ hearts given an 8-card clubs must be close to 50%. (It is 2/3 with a 8221, 1/3 with a 8311, 1/3 with 8320 and 1/6 with 8410). Given our own shortness in spades and RHO failure to overcall the probability must be slightly larger. I would guess the chance of going down DD to be some 50%.
Single-dummy there is the added chance of a minor lead and p having a singleton ♦ and doubleton ♠. Or maybe he is allowed to have ♦Qx.
#9
Posted 2008-February-21, 06:45
Poky, on Feb 21 2008, 11:04 AM, said:
cardsharp, on Feb 21 2008, 11:34 AM, said:
What constraints you used?
Can you repeat, please, a simulation with these:
- fix: ♣KQJxxxxx;
- fix: 6-8 HCP (no big values outside, max Q or JJ);
- fix: no 4M, no 4♦.
TY.
P.S. What program do you use for these simulations?
This is a lot stricter than the parameters I used last time and it took significantly more time to generate the hands. Personally I think they are too strict; 4m do not happen that often and putting additional constraints on them mean that they'll be even rarer.
This was confirmed by the fact my database of hands only contained 30 that matched the criteria.
Of these, 11 (37%) made 11 tricks of which one (3%) made 12 tricks.
Of course these criteria greatly increase the chances of two spade losers together with the heart ace.
Paul
PS I use DealMaster Pro.
#10
Posted 2008-February-21, 08:05
#11
Posted 2008-February-21, 08:09
The_Hog, on Feb 21 2008, 05:05 PM, said:
One of the rare occasions where I disagree with the Hog...
I suspect that we're going to lose three tricks before we cash 11 a large percentage of the time.
I lean towards passing
#12
Posted 2008-February-21, 08:10
The_Hog, on Feb 21 2008, 02:05 PM, said:
My view too. Life's too short to worry about this type of problem.
The percentages are all well and good, but it's not a problem that comes up with sufficient frequency that they mean very much.
Paul
#13
Posted 2008-February-21, 08:15
#14
Posted 2008-February-21, 11:15
#15
Posted 2008-February-21, 12:16
Shape Rel Prob Non-Club Losers
2-2-1-8 16.3% 3
2-1-2-8 16.3% 3
1-2-2-8 13% 2
3-1-1-8 12.2% 3
1-3-1-8 7.6% 2
1-1-3-8 7.6% 2
3-0-2-8 5.4% 2
3-2-0-8 5.4% 3
2-0-3-8 4.2% 2.5
2-3-0-8 4.2% 3
0-2-3-8 2.8% 1
0-3-2-8 2.8% 1
1-0-4-8 1.3% 1.5
0-1-4-8 1% 1
The above probabilities are calculated just based on the known hand's suits, and assumes no useful honor cards except in clubs. In addition, the losers only count top tricks and assume we will take a ruffing finesse if necessary to dispose of diamond losers. It doesn't count the possibility of defensive ruffs, etc. The chances for a club loser are quite small - something like 8% of the time we'll lose a club (missing the K or it doesn't drop), given that all hands with 8 clubs and 2+ of KQJ are equally likely and conditioned on our club holding.
This leads to these outcomes (again ignoring the club suit):
Prob(4♣) 56.5%
Prob(5♣) 36.3%
Prob(6♣) 7.2%
I will add that if your partner makes undisciplined 4♣ preempts on 7♣(321) shape you are much worse off. Now you are very likely to have both 2 spades and a heart loser and the contract probabilities drop to:
Prob(4♣) 72.4%
Prob(5♣) 26.7%
Prob(6♣) 0.9%
Now game is quite poor.
#16
Posted 2008-February-21, 12:23
#17
Posted 2008-February-21, 12:24
Poky, on Feb 21 2008, 04:56 AM, said:
...
1248
...
Now that's some shape! Another 15 card hand!
#19
Posted 2008-February-21, 12:33
jdonn, on Feb 21 2008, 01:23 PM, said:
...if they're on crack...
#20
Posted 2008-February-21, 12:49
cardsharp, on Feb 21 2008, 07:45 AM, said:
How often can the opponents make 4♠?
What are the passers going to do after 4♠ on their left, passed back to them?

Help
