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逼叫性1nt后的15p再叫问题

#1 User is offline   lycier 

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Posted 2013-March-17, 02:29



逼叫性1nt后,北家15p再叫问题:你觉得怎样再叫性描述才算充分呢?
2?还是3?还是其他?
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#2 User is offline   3ntmk 

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Posted 2013-March-17, 04:02

显然,具有p15和一个6张套具备了邀请的实力。邀请手段应该可以拓展并加以比较利用。

如果,把CA换为SA,可以简单的跳3S邀请,表示S的独立主打套。

所给牌面不能独立主打,可以通过bart,即再叫2C,进一步交换信息,查探有无成局或成个什么样的局。

1S - 1N
2C - 3H(6张H的邀请,当然你会4h)
-------2D (=示强)

2nt = 均型,或较差的6张s,p15-17
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#3 User is offline   sleekrain 

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Posted 2013-March-18, 00:51

打巴特约定叫好像是2C吧,如果没有约定叫,我倾向叫2S,虽然埋没点力,但点质量欠佳;3S叫过,套嵌张结构有疑问,牌型偏均型。
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#4 User is offline   lycier 

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Posted 2013-March-18, 02:02

我认为:


(一)

1---1nt---2
如果搭档定约开叫人再叫2仅保证2张+且有逼叫一轮的含义(再叫2表示4张+),3ntmk的意见有可行性。

(二)

基本认识:

一般尺度是:15p的6张均型,再叫时按低限处理,也就是再叫2,而3的跳叫危险危险。
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#5 User is offline   yunling 

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Posted 2013-March-18, 05:49

2,烂的主套,缺乏中间张支持的边花大牌都很糟糕。
2没意思,因为这手牌你更关注PD对S的支持,这一点2完全问不出来。
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#6 User is offline   wuhuan 

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Posted 2013-March-18, 08:45

学习了!
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#7 User is offline   lycier 

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Posted 2013-April-19, 06:05

开叫人再叫2的好处在于可以探查应叫人是否有可邀请进局的实力。具体说:
再叫2后,看看应叫人是否有能力叫出2(表示8P+,也许含5张)接力。
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#8 User is offline   xuefeier 

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Posted 2013-April-20, 04:35

er老师分析的好
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#9 User is offline   ynhhyjb 

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Posted 2013-August-09, 03:03

还有就是15P,S-H是5-4和5-5,又应该怎么叫?16、7P呢,又怎么叫?
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#10 User is offline   dongfz 

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Posted 2013-August-09, 19:49

Gazzilli约定叫
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#11 User is offline   ynhhyjb 

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Posted 2013-August-10, 06:33

 dongfz, on 2013-August-09, 19:49, said:

Gazzilli约定叫

Gazzilli约定叫增加记忆量,我想用巴特应该可以解决。
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