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T9x

#1 User is offline   gwnn 

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Posted 2010-June-02, 05:07

The bidding went, starting at your right,

1S-p-1N-2D
4S-end

You have T9x of diamonds. In your partnership, which diamond do you lead? What is the rule that this situation is under? What if the bidding have instead gone 1S-p-4S-end (and for some reason you want to lead a diamond from T9x)?
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#2 User is offline   Free 

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Posted 2010-June-02, 05:08

♦T in both cases
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#3 User is offline   kgr 

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Posted 2010-June-02, 06:01

We play highest of sequence with even nbr of cards and 2nd with odd number of cards, but we don't do this if partner did bid the suit.
T in 1st case; 9 in 2nd
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#4 User is offline   Phil 

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Posted 2010-June-02, 08:13

The x. Don't we want to give count to partner?

I suppose if dummy comes down with KJ8 and declarer a void I might regret my choice. Or KJ8x / x and declarer has only two entries to the board.
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#5 User is offline   pooltuna 

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Posted 2010-June-02, 08:42

Phil, on Jun 2 2010, 09:13 AM, said:

The x. Don't we want to give count to partner?

I suppose if dummy comes down with KJ8 and declarer a void I might regret my choice. Or KJ8x / x and declarer has only two entries to the board.

I don't know where the break even point is but the T from T92 and the 2 from T82
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#6 User is offline   Jlall 

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Posted 2010-June-02, 13:58

Normally the ten, in the case of partner bidding the suit and you not having raised you might choose to lead small.
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